(2x+3)^2=(2x+3)(2x+3)

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Solution for (2x+3)^2=(2x+3)(2x+3) equation: 



(2x+3)^2=(2x+3)(2x+3)

We move all terms to the left:

(2x+3)^2-((2x+3)(2x+3))=0

We multiply parentheses ..

-((+4x^2+6x+6x+9))+(2x+3)^2=0



We calculate terms in parentheses: -((+4x^2+6x+6x+9)), so:

(+4x^2+6x+6x+9)

We get rid of parentheses

4x^2+6x+6x+9

We add all the numbers together, and all the variables

4x^2+12x+9

Back to the equation:

-(4x^2+12x+9)



We get rid of parentheses

-4x^2-12x+(2x+3)^2-9=0

We move all terms containing x to the left, all other terms to the right

-4x^2-12x+(2x+3)^2=9

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